Blocks of masses 
and 
are arranged in a line on a frictionless floor. Another block of mass 
, moving with speed 
along the same line (see figure) collides with mass 
in perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic. By the time the last block of mass 
starts moving the total energy loss is 
of the original energy. Value of ' 
' is close to:
Text Solution
Verified by ExpertsA
There will be total 4 collisions in each collision K.E. decreasing by 
i.e. 
loss
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